UnaGPT · 中学版

理科

深入剖析物理运算、化学图像分析与生物长问答，精准找出概念盲点，对比评分准则评估论述完整度。

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化学科

算式与符号手写辨识

学生以纸笔书写化学算式与科学符号，拍照上传，AI 准确辨识科学符号并自动分行，转换为可编辑的数码文字。

科学符号自动分行
化化学科
学生手写上传
學生手寫
OCR数码化
转换为数码文字
识别文字
PbO+SO42−→Pb+SO2
✓科学符号✓自动分行
物理科

计算应用题

深入剖析学生运算过程，精准找出学生忽略的物理概念盲点。

逐步运算单位处理概念盲点
学生物理 · 计算应用题
问题 (3 分)
A copper block of mass 150g is heated to a few hundred °C (T °C), then quickly transferred into a polystyrene cup containing 500g of water. Assume no heat is lost. The water temperature rises from 22°C to 29°C. Estimate T. (c copper=385, c water=4200 J kg⁻¹°C⁻¹)
答案 · 提交 #1
4200×(29−22)×0.5 = 14700J
385×0.15×(T−29) = 14700
T−29 = 25.45
T = 54.5
分数详情
最终得分：2
Calculation of energy gained by water
The expression for the energy gained by the water is correctly formulated and calculated.
1
Expression for energy lost by copper block
The expression for the energy lost by the copper block, involving the unknown initial temperature T, is correct.
1
Calculation of initial temperature T
The equation equating energy lost and gained was set up correctly. However, a calculation error occurred when solving for (T−33), giving an incorrect final value for T.
0
物理科

精准判读受力分析 NEW

AI 解读自由体图的受力分析，检视各力的符号、方向与分量是否正确，并逐步核对三角比运算，指出单位及计算上的错误，助学生巩固力学概念。

自由体图受力分析三角比运算
学生图像作答物理 · 自由体图
Question · Question 3 [6 marks]
A block of mass 2.0 kg rests in equilibrium on a rough plane inclined at 30° to the horizontal. (Take g = 10 N kg⁻¹.) (a) Draw a labelled free-body diagram of the forces on the block. (3) (b) Find the magnitude of the friction force on the block. (3)
Student's Answer
物理 · 自由體圖
AI Result
(a) Weight force arrow
The weight force is correctly drawn acting vertically downwards and labelled as W.
1
(a) Normal reaction force arrow
The normal reaction force is labelled as W cos 30° instead of a standard symbol like R or N. A free-body diagram should show the actual forces rather than their magnitudes or components.
0
(a) Friction force arrow
The friction force is correctly drawn parallel to the plane, pointing upwards, and labelled as f.
1
(b) Equating friction to weight component
The equation f = W sin 30° correctly resolves forces parallel to the inclined plane.
1
(b) Substitution of values
The values for mass and gravity are correctly substituted as 2(10)sin 30°.
1
(b) Final answer
The calculated answer is incorrect and has an incorrect unit.
0
Free-body diagram
The weight W and friction f are drawn and labelled correctly. However, the normal reaction force is labelled with its magnitude W cos 30° instead of its symbol. Furthermore, an extra force representing the component of weight parallel to the plane (W sin 30°) is included. In a standard free-body diagram, only the actual forces acting on the object should be drawn, and their components should not be included alongside them.
f = W sin 30° = 2(10)sin 30° = 17.32 g
The formula and substitutions are correct. However, the calculation of 2(10)sin 30° is incorrect. Since sin 30° = 0.5, the correct value should be 10. The value 17.32 appears to have been calculated using cos 30° instead. Additionally, the unit of force should be Newtons (N), not g.
化学科

图像分析题

AI 智能解读问题中的图像与文字信息，全面分析学生文字作答思路与准确性。

图文并读方程式判断焓变计算
学生化学 · 图像分析题
问题 (2 分)
Ethanol (C₂H₅OH) is a liquid fuel. In a school experiment, the enthalpy change of combustion of ethanol was determined using the set-up shown. Burning 0.230 g of ethanol raised the temperature of 150.0 g of water by 9.6 °C. Calculate the enthalpy change of combustion of ethanol, in kJ mol⁻¹, under these conditions. (Assume the heat capacity of the aluminium can is negligible and the specific heat capacity of water is 4.20 J g⁻¹ K⁻¹.) (Relative atomic masses: H = 1.0, C = 12.0, O = 16.0)
實驗裝置
分数详情
最终得分：2
Calculation of energy absorbed by water
The calculation correctly determines the energy absorbed by the water using the given data.
1
Calculation of enthalpy change of combustion per mole
The calculation for the number of moles of ethanol used an incorrect mass value …
1
内容分析
Enthalpy change = −6.048⁄150.012 × 2 + 6 + 16
The formula for enthalpy change per mole (ΔH=−q/n) is used. The value for heat released (−q) is correctly taken from the previous step. However, the calculation for the number of moles (n) incorrectly uses the …
= −1.86 kJ mol⁻¹
This final value is the result of the calculation in the previous line. Although the arithmetic is performed correctly based on the …
化学科

实验装置图 NEW

AI 解读实验装置图，检视反应容器、试剂标示与气体收集方法是否正确，指出装置选用及标示上的不足，助学生掌握实验设计的关键概念。

实验装置图气体收集仪器标示
学生图像作答化学 · 实验装置图
Question · Question 1 [6 marks]
In the laboratory, carbon dioxide is prepared by adding dilute hydrochloric acid to marble chips. (a) Draw a labelled diagram of the apparatus used to prepare and collect gas jars of carbon dioxide. (4) (b) Write the equation for the reaction. (2)
Student's Answer
化學 · 實驗裝置圖
AI Result
Part (a) Diagram
The diagram correctly illustrates the reaction vessel, a closed system, the reagents, and the downward delivery method. However, the collection vessel drawn and labelled is a glass tube rather than a gas jar.
3
Diagram of the apparatus
The reaction vessel containing the appropriately labelled reagents and the downward delivery system are well depicted. Carbon dioxide is denser than air, making downward delivery an appropriate collection method. To fully address the question, a gas jar should be drawn and labelled as the collection vessel instead of a generic glass tube. Incorporating a thistle funnel or dropping funnel into the stopper would better represent the typical laboratory setup, allowing the acid to be added to the marble chips safely without losing gas to the surroundings.
化学科

能量级图概念 NEW

AI 解读能量级（能量曲线）图，检视曲线形状、活化能与焓变的标示是否正确，并指出概念上的错误，助学生厘清放热反应的能量变化。

能量级图活化能放热反应
学生图像作答化学 · 能量级图
Question · 问题 [4 分]
甲烷的完全燃烧为放热反应。(a) 绘画该反应的能量级（能量曲线）图，标示活化能 Eₐ 及反应的焓变。(3) (b) 说明焓变是正值还是负值。(1)
Student's Answer
化學 · 能量級圖
AI Result
(a) 能量曲线与标示
学生成功绘画了放热反应的能量曲线形状（反应物的能量水平高于生成物），并正确标示了活化能（Eₐ）。然而，焓变的标示符号不正确，因此未能获得该部分的分数。
2
Reasoning Issues
概念错误 (Conceptual Error)
b) 正值
甲烷的燃烧为放热反应，代表反应过程中系统会释放能量到环境中。由于生成物的总能量低于反应物的总能量，因此反应的焓变（ΔH）必须为负值。
生物科

长问答阐述题

对比评分准则，评估学生答案的完整度与逻辑性，同时检视论述表达是否清晰、有条理。

论述完整度逻辑分析内容分析
学生生物 · 长问答阐述题
问题 (11 分)
In agricultural practice, some crops are reproduced asexually to improve production efficiency. An increase in yield is observed due to rising global temperature. Explain the increased yield due to global warming and the rationale behind the scientists' concern.
答案 · 提交 #1
The increased yield of these crops due to global warming bring different impact and the rationale behind the concern of the scientists. Crops are reproduced asexually to improve production efficiently…
Part 1: Increasing Yields
No relevant explanation is provided for why global warming increases crop yield. …
0
Part 2: Rationale behind the scientists' worry
The answer states that asexually reproduced crops have the same gene/DNA and that there is no variation …
3
内容分析
The increased yield of these crops due to global warming. Crops are reproduced asexually to improve production efficiently. The crops are reproduced asexually, they have the same gene, DNA, the xxx of crops can pass to the next generation. There are no xxx are needed. It have a faster reproduction.
This paragraph does not address the question of why global warming increases yield. It repeats information about asexual reproduction and genetic identity, but does not explain the link to increased yield. The use of 'xxx' suggests missing or unclear content. To improve, the paragraph should explain that higher temperatures can speed up …
生物科

判读神经元标示图 NEW

AI 准确判读器官与细胞标示图，检视各部结构的标示位置是否合理，并对照评分准则逐项给分，指出可补充的标示，助学生巩固生物概念。

标示图判读结构标示概念补充
学生图像作答生物 · 神经元标示图
Question · Question 1 [5 marks]
(a) Draw a labelled diagram of a motor neurone. (4) (b) State the function of the myelin sheath. (1)
Student's Answer
生物 · 神經元標示圖
AI Result
Diagram of motor neurone
The drawing shows the general form of a motor neurone and correctly labels key parts including dendrites, cell body, nucleus, long axon, myelin sheath and axon terminals. This meets the required features for the diagram part.
4
Labelled neurone diagram with labels for dendrites, cell body, nucleus, long axon, myelin sheath and terminal region.
The organisation is clear and the labelled features are placed in sensible positions, so the diagram is easy to follow. The overall shape matches a motor neurone well enough for full credit on this part. A small weakness is that the nodes of Ranvier are not clearly labelled, though enough correct structures are present. A stronger version could make the gaps in the myelin sheath more distinct and label them directly.
生物科

判读数据作图题 NEW

AI 解读学生的数据作图，检视坐标轴标示、单位与数据点绘画是否准确，并对照评分准则指出标题、坐标轴及连线上的不足，助学生掌握实验数据处理。

数据作图坐标轴标示平滑曲线
学生图像作答生物 · 酶速率作图
Question · 第 2 题 [6 分]
下表为某酶催化反应在不同温度下的速率。(a) 绘画速率对温度的图并画出平滑曲线。(3) (b) 说出最适温度。(1) (c) 解释最适温度以上曲线的形状。(2)
温度 (°C)102030374555
速率 (任意单位)0.100.300.701.000.500.05
Student's Answer
生物 · 酶速率作圖
AI Result
部分 (a)
学生绘画的图表没有标示坐标轴的单位（y轴缺少“任意单位”，x轴缺少“°C”），且没有正确地将数据点绘画在坐标图上，只是画出了一个大致的趋势，未能满足评分参考中对于标题、坐标轴标示及正确绘点连线的要求。
0
2026 全新功能 NEW

Una 题库 · 理科：中一至中六课程题目一应俱全

中一至中六理科由知识结构出发 —— 逐个考点备课、出题与复核；每题附评分标准与示例答案，一键导出至 UnaGPT AI 自学系统自动批改。

  • 中一至中六理科：27,360 条题目 · 855 个考点
  • 中英双语对照，界面与题目一键切换
  • 草稿 → 复核 → 发布，教师复核流程把关
  • 多元题型：多选／简答／结构／资料回应／写作／图像作答
覆盖范围
中一至中六
中文英文数学文科理科商科其他
理科 · 知識點樹
① 知识点树 —— 理科：科目 → 纲领 → 主题 → 考点
物理 試題範例
② 物理试题 —— 运动图线的绘画与诠释 含图像
化学 試題範例
③ 化学试题 —— 周期表的结构 含图像
生物 試題範例
④ 生物试题 —— 家系图分析 含图像
組合科学 试题范例
⑤ 组合科学试题 —— 盐的制备
师生感言

学校与师生的真实反馈

物理科学生的文字表达能力普遍较为薄弱，过去教师需耗费大量时间来处理他们的文字问题。尽管文字答题所占的分数比例通常不高，然而教师却需付出更多的精力来批改，这样的效率显然不理想。如今有了 UnaGPT，该系统能迅速解决大部分的文字问题，使教师能够释放出更多的时间，专注于其他分数比例更高的教学内容。

蔡玉成
蔡玉成物理科老师 · 圣公会林裘谋中学
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